C++ កូដ: សំរាប់បំលែង ចំនួនគោល១០ ទៅគោល២ Decimal to Binary Converter

មានវិធីជាច្រើនដើម្បីសរសេរពេលនេះខ្ញុំសូមយកចំនួនពីរគឺ
វិធីទី១៖<pre>#include<iostream.h> #include<conio.h> main() { int n; int k=25; char str[] = " "; // (k+1) spaces, and an automatic '\0' at the end cout<<"Enter binary equivalent you wan to calculate."; cin>>n; while(n>1) { str[k--]=(n%2) + '0'; // remember, 0 and '0' are two different values! n=n/2; } cout<<"\n\t The binary equivalent is "<<str getch(); return();</pre> វិធីទី២៖<pre>#include <iostream.h> int main() { long dec,rem,i=1,sum=0; cout<<"Enter the decimal to be converted:"; cin>>dec; do { rem=dec%2; sum=sum + (i*rem); dec=dec/2; i=i*10; }while(dec>0); cout<<"The binary of the given number is:"<<sum<<endl; cin.get(); cin.get(); return 0; }</pre>
វិធីទីពីរនេះអាចបំលែងបានខ្ពស់បំផុត គឺ៖ ៩៩៩